(4x^2+3)(2x-3)=0

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Solution for (4x^2+3)(2x-3)=0 equation: 


Simplifying
(4x2 + 3)(2x + -3) = 0

Reorder the terms:
(3 + 4x2)(2x + -3) = 0

Reorder the terms:
(3 + 4x2)(-3 + 2x) = 0

Multiply (3 + 4x2) * (-3 + 2x)
(3(-3 + 2x) + 4x2 * (-3 + 2x)) = 0
((-3 * 3 + 2x * 3) + 4x2 * (-3 + 2x)) = 0
((-9 + 6x) + 4x2 * (-3 + 2x)) = 0
(-9 + 6x + (-3 * 4x2 + 2x * 4x2)) = 0
(-9 + 6x + (-12x2 + 8x3)) = 0
(-9 + 6x + -12x2 + 8x3) = 0

Solving
-9 + 6x + -12x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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